The amplitude of the electric field is 0.9 v/m 42 km from a radio transmitter. what is the total power emitted by the transmitter, if one assumes that the radiation is emitted isotropically (uniformly in all directions)? the impedence of free space is 377 ω . answer in units of w.

The power is found to be P = 14250600 W

Explanation:

First we find the voltage or potential difference at the position:

Voltage = Amplitude of Field x Distance

Voltage = V = (0.9 V/m)(42000 m)

V = 37800 volts

Now, we know the formula of electric power is:

Power = Voltage x Current

P = V I

but, from Ohm's Law:

V = I R

I = V/R

Therefore,

P = V²/R

Resistance = real part of impedence = 377 Ω

Therefore,

P = (37800 V)(377 Ω)

P = 14250600 W

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

explanation:

earth's surface is mainly heated by the absorption of infrared radiation from the sun.

evaporation occurs because molecules in liquid water are warmed ( usually by the sun) and vibrate quicker, becoming less dense and rise.

condensation occurs because molecules in water vapor are cooled and therefore vibrate more slowly thus becoming more dense and eventually fall to earth.

lines of equal barometric pressure on a weather map are called: isobars : lines of equal temp on a weather map are called: isotherms.​