A430 g soccer ball lying on the ground is kicked and flies off at 25 m/s. if the duration of the impact was .01 s, what was the average force acting on the ball?

Explanation:

Force is given by rate of change of momentum.

Mass of soccer ball = 430 g = 0.43 kg

Initial velocity = 0 m/s

Final velocity = 25 m/s

Change in momentum = 0.43 x 25 - 0.43 x 0

Change in momentum = 10.75 kg m/s

Time taken = 0.01 s

Rate of change of momentum = Change in momentum ÷ Time

Rate of change of momentum = 10.75 ÷ 0.01

Rate of change of momentum = 1075 N

Force = 1075 N

The average force acting on the ball is 1075 N in the direction of travel of ball.

ill do it for 100, also this isnt 80 its 40

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more