Point charges q1=− 5.00 nc and q2=+ 5.00 nc are separated by distance 3.30 mm , forming an electric dipole.

a) find the magnitude of the electric dipole moment. express your answer in coulomb meters to three significant figures.

b) what is the direction of the electric dipole moment?

from q1 to q2
from q2 to q1
c) the charges are in a uniform electric field whose direction makes an angle 36.1 ∘ with the line connecting the charges. what is the magnitude of this field if the torque exerted on the dipole has magnitude 7.00×10−9 n⋅m ?

express your answer in newtons per coulomb to three significant figures.

(a) The electric dipole moment is equal to 16.5×10^-12 Cm

(b) The electric dipole moment is directed along the dipole axis from the negative charge to the positive charge.

(C) Torque on the dipole is equal to the products of the Electric field vector and the dipole moment

The magnitude is given by

pE×Sin(phi)

Explanation:

The dipole moment is equal to the productof the magnitude of the charge and the distance of separation between the charges.

The detailed solution to the problem is contaimed in the attachment below.

Thank you for reading.

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)

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