An object on a vertical spring oscillates up and down in simple harmonic motion with an angular frequency of 14.2 rad/s. calculate the distance d by which the spring stretches from its unstrained length when the object is allowed to hang stationary from it.

0.04865 m

Explanation:

k = Spring Constant

m = Mass

d = Distance

g = Acceleration due to gravity = 9.81 m/s²

Angular frequency is given by

At equilibrium we have

The distance by which the spring stretches from its unstrained length is 0.04865 m

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2