A0.30 kg mass is sliding on a horizontal, frictionless air track with a speed of 4.0 m/s when it instantaneously hits and sticks to a 2.0 kg mass initially at rest on the track. the spring constant is 100 n/m . the other end of the spring is fixed. a. determine the following for the 0.30 kg mass immediately before the impact: i. its linear momentum ii. its keb. determine the following for the combined masses immediately after the impact: i. the linear momentum in. the kec. besides the fact that the objects stick together, what other clue lets you know that this was an inelastic collision

Answer

given,

mass of block 1, m = 0.3 Kg

speed of block 1, v = 4 m/s

mass of second block,M = 2 Kg

initial speed of block = 0 m/s

spring constant, k = 100 N/m

a) for block 1

  linear momentum before collision

   P₁ = m v = 0.3 x 4 = 1.2 Kg.m/s

  Kinetic energy

b) After impact

  final velocity calculation

 using conservation of momentum

  m v  = (m + M )v_f

   0.3 x 4 = 2.3 x v_f

    v_f = 0.522 m/s

   Linear momentum

   P₂ = (m+M) v_f

   P₂ = 1.5 x 0.522

   P₂ = 0.783 kg.m/s

   Kinetic energy

answer: option c.

explanation:

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this