Physics, 24.01.2020 00:31 seanisom7

The orbital period of a satellite is 2 × 106 s and its total radius is 2.5 × 1012 m. the tangential speed of the satellite is m/s. (round to the nearest whole number, do not add any punctuation.)

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Answer from: nickboy52210

The tangential speed of the satellite is 7853982 m/s

Explanation:

To find the tangential speed of the satellite we need the circumference of the orbit.

The circumference is $2\pi r$ , when the radius of the orbit is . For the case of our satellite, $r=2.5*10^{12}\:m$

$\therefore 2\pi r= 2\pi (2.5*10^{12}\:m)= 1.570796327*10^{13}\: m$

Now the tangential speed v_t is easy to calculate because it is just the circumference divided by period:

$v_t=\frac{2\pi r }{T}$

we put in the numbers and get:

$v_t=\frac{1.570796*10^{13} }{2*10^6}=\boxed{7853982\:m/s}$

Answer from: Quest

Wish i knew this to !

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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The orbital period of a satellite is 2 × 106 s and its total radius is 2.5 × 1012 m. the tangential...

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