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Physics, 24.01.2020 05:31 patrickgonzalezjr13

At time t = 0 an elevator starts moving upward from the ground at a constant speed vo. at a later time t = t1 = 2.35s a marble is "let go" through the floor. in other words, imagine a marble resting on the floor of the elevator and a trap door of sorts opening up from under the marble. the marble then hits the ground at a still later time t = t2 = 11.2s.
1. what is the maximum height (above the ground) that the marble reaches in this process?

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