Two charges are located in the x – y plane. if q 1 = − 3.65 nc and is located at ( x = 0.00 m , y = 0.600 m ) , and the second charge has magnitude of q2 = 4.20 nc and is located at ( x = 1.10 m , y = 0.800 m ) , calculate the x and y components, ex and ey , of the electric field, → e , in component form at the origin, ( 0 , 0 ) . the coulomb force constant is 1/(4πϵ0 ) = 8.99 × 10^9 n ⋅ m^2 /c^2.

Ex = 15.505 N/C

Ey = 79.144 N/C

Explanation:

Particle 1

Away from the particle at (0,0) due to + charge

Particle 2

Towards from the particle at (0,0) due to - charge

Resultant Electric field in y direction

Resultant Electric field in x direction

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

i think its c if i'm wrong