Find the concentration of htions at a ph = 11 and
ph = 6. then divide the concentration of h+ ions at a
ph = 11 by the of h+ ions at a ph = 6. record your
answer in table c.
what is the concentration of h+ ions at a ph = 11?
mol/l
what is the concentration of htions at a ph = 6?
mol/l
how many fewer h+ ions are there in a solution at a
ph = 11 than in a solution at a ph = 6?

Abecause its more effective

For me a person with a phd and who knows what there talking about.i know the chances of a radiation leak is low but if it does the area within a 96.3 mile radius would be unusable because of contamination

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.