An average human weighs about 650 n. if each of two average humans could carry 1.0 c of excess charge, one positive and one negative, how far apart would they have to be for the electric attraction between them to equal their 650-n weight?

r = 3721.04 m          

Explanation:

Given that,

Weight of human, F = 650 N

Charge on two humans,

We need to find the distance between charges if the electric attraction between them to equal their 650 N weight. It is given by :

r = 3721.04 m

So, the distance between charges is 3721.04 m if the electric attraction between them to equal their 650 N weight. Hence, this is the required solution.

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i think the answer would be reserve.