In a vacuum, two particles have charges of q1 and q2, where q1 = +3.11 μc. they are separated by a distance of 0.241 m, and particle 1 experiences an attractive force of 3.44 n.
what is the magnitude and sign of q2?

Charge of particle 2,

Explanation:

Given that,

Charge 1,

The distance between charges, r = 0.241 m

Force experienced by particle 1, F = 3.44 N

We need to find the magnitude of electric charge 2. It can be calculated using formula of electrostatic force. It is given by :

or

So, the magnitude of electric charge 2 is . Since, the force is attractive then the magnitude of charge 2 must be negative.

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

kepler used the data from tycho blahe (his mentor) to construct the laws of planetary motion.