An electric field can induce an electric dipole in a neutral molecule (or atom) by pushing the positive and negative charges inside the molecule in opposite directions. the dipole moment of the induced dipole is directly proportional to the electric field at the molecule. that is, p=αe , where p is the induced dipole moment, α is called the polarizability of the molecule, and e⃗ is the electric field at the molecule. a stronger electric field at the molecule results in a more polarized molecule and causes a larger dipole moment p . a molecule with a larger polarizability, α, will be more polarized when subjected to the same electric field. find an expression for the magnitude of the force f⃗ ionondipole. express your answer in terms of the variables q, r, α and appropriate constants.

F is the electric force, q is the dipole charge, E is the electric field intensity, p is dipole moment, ∆ represent polarizability

F = qE. p = ∆E.

Therefore F(The magnitude of force) = (q*p)/∆.

Note the ∆ is used to denoted alpha here

Explanation:

Useful Explanation

The derived electrostatic forces act on the end charges of the dipole. Because the electric field is uniform, those forces act in opposite directions and with the same magnitude

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

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