Old faithful geyser in yellowstone national park shoots water every hour to a height of 40.0 m. with what velocity does the water leave the ground? (disregard air resistance. g 9.81 m/s) a. 7.00 m/s c. 28.0 m/s d. 14.0 m/s b. 19.8 m/s 30.) a moderate force will break an egg. however, an egg dropped on the road usually breaks, while one dropped on the grass usually does not break because for the egg dropped on the grass, a. the b. the change in momentum is greater. time interval for stopping is greater. the change in momentum is less the time interval for stopping is less. c. d.

1) The water leaves the ground at a velocity of 28 m/sec. Therefore the correct option is B).

2) An egg dropped on the road usually breaks, while one dropped on the grass usually does not break because contact force is significantly lower and time interval is greater.

Given :

Yellowstone National Park shoots water every hour to a height of 40 m.

Solution :

1) From conservation of momentum -

KE = PE

 --- (1)

where,

h = 40 m

Now put the values of g and h in equation (1) we get,

v = 28 m/sec

2) According to the impact theorem, the egg does not break on the grass since contact force is significantly lower and time interval is greater. Therefore, the correct option is B).

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a) , b) B. Time interval for stopping is greater.

Explanation:

a) The initial velocity is found with the help of the Principle of Energy Conservation:

b) According to the Impact Theorem, the egg does not break on the grass since contact force is significantly lower and time interval is greater. Hence, the right answer is option B.

are there options? cause you ain’t. real specific

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