A1.0-cm-diameter pipe widens to 2.0 cm, then narrows to 0.5 cm. liquid flows through the first segment at a speed of 9.0 m/s

a: what is the speed in the second segment? m/s
b: what is the speed in the third segment? m/s
c: what is the volume flow rate through the pipe? l/s

(a) Speed in the second segment=2.25 m/s

(b) Speed in the third segment=36 m/s

(c) Volume=0.02826 L/s

Explanation:

Given Data

r₁=5×10⁻⁴m

r₂=10⁻³m

r₃=2.5×10⁻⁴ m

v₁= 9.0 m/s

For (a) speed in the second segment

From continuity equation

For (b) speed in the third segment

For (c) the volume flow rate through the pipe

The volume flow rate is the same in all three segments and is given as:

As per requirement of question we need to convert volume cubic meter/second to Litre/second for that we need to "multiply the volume /second value by 1000"

So

Volume=(2.86×10⁻⁵ ×1000) L/s

Volume=0.02826 L/s

the device is called “ rocket engine”

a longitudinal wave moves energy that is to the direction of the wave’s movement. - true