Point charge q1 and q2 both of 22nc are separated by a distance of 58cm along horizontal axis point a is located 40cm from q1 and 18 cm from q2. what is the magnitude and direction of the electric field at point a

E = 4.01×10^6 N/C

direction is toward q2

Explanation:

q1 = q2 = 12micro-C = 12×10^-6C

r1 = 18cm = 0.18m

r2 = 40cm = 0.40m

k = 9×10^9

E1 = kq1/(r1)²

E1 = 3.33×10^6 N/C

E2 = kq2/(r2)²

E2 = 6.75×10^5 N/C

Enet = E1 + E2

= 3.33×10^6 + 6.75×10^5

= 4.01×10^6 N/C

direction is toward q2

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min