Aclosed system consists of 0.3 kmol of octane occupying a volume of 5 m3 . determine

a) the weight of the system, in n, and
(b) the molar- and mass-based specific volumes, in m3 /kmol and m3 /kg respectively. let g = 9.81 m/s2

(a). The weight of the system is 336.32 N.

(b).  The molar volume is 16.6 m³/k mol.

The mass based volume is 0.145 m³/kg.

Explanation:

Given that,

Weight of octane = 0.3 kmol

Volume = 5 m³

(a). Molecular mass of octane

We need to calculate the mass of octane

Mass of 0.3 k mol of octane is

We need to calculate the weight of the system

Using formula of weight

Put the value into the formula

(b). We need to calculate the molar volume

Using formula of molar volume

Put the value into the formula

We need to calculate the mass based volume

Using formula of mass based volume

Put the value into the formula

Hence, (a). The weight of the system is 336.32 N.

(b).  The molar volume is 16.6 m³/k mol.

The mass based volume is 0.145 m³/kg.

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