Achild on a playground swings through a total of 32 degrees. if the displacement is equal on each side of the equilibrium position, what is the amplitude of this vibration?

A = y/cos32

That is the amplitude A in terms of the displacement y.

Explanation: Since the displacement in the question In the question is the same in both direction, it is a Simple Harmonic Motion problem. In s.h.m the amplitude of displacement A is related to the displacement itself y by this simple equation

y = A* cos(theta)

So, A = y/cos(theta)

A = y/cos32.

If the magnitude of the displacement y is given, you just substitute in.

the answer is b i think

true is the correct answer

hope i