Another droplet of the same mass falls 8.4 cm from rest in 0.250 s, again moving through a vacuum. find the charge carried by the droplet.

The charge carried by the droplet is

Explanation:

Given that,

Distance =8.4 cm

Time = 0.250 s

Suppose tiny droplets of oil acquire a small negative charge while dropping through a vacuum in an experiment. An electric field of magnitude points straight down and if the mass of the droplet is

We need to calculate the acceleration

Using equation of motion

Put the value into the formula

We need to calculate the charge carried by the droplet

Using formula of electric filed

Put the value into the formula

Hence, The charge carried by the droplet is