At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 344 n/c. at a distance r2 from the charge, the field has a magnitude of 171 n/c. find the ratio r2/r1.

To solve this problem we will apply the concepts related to the electric field. This definition is based on the proposal by Coulomb and will be described in its two states. Under this relationship we will obtain the radius of the distances depending on the elective field.

The electric field strength of the charge from a distance is,

The electric field strength of the charge from a distance is,

The relation between the electric field strengths and is

and can be written as

Replacing we have,

The ratio of the distances and is 1.39

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we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer