The electric field strength 3.5 cm from the surface of a 10-cm-diameter metal ball is 70,000 n/c. what is the charge (in nc) on the ball?

To develop this problem, we will apply the concepts related to the Indian electric field from Coulomb's law. According to the values given we have to the electric field is

Distance from the center of the ball to the point of consideration is

Now the electric field strength is

Here,

k = Coulomb's Constant

q = Charge

r = Distance

Rearrange to find the charge,

Replacing,

Therefore the charge on the ball is 56.194nC

explanation:

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