String is fixed at two ends with distance 1.5 m. its mass is 5 g and the tension in the string is 50 n and it vibrates on its third harmonic. a) what is the wavelength of waves of the string. b) what is the frequency of the waves. c) the vibrations

(a). The wavelength of waves of the string is 1 m.

(b). The frequency of the waves is 122.4 Hz.

(c). The wavelength of the sound emitted by the string is 2.8 m.

Explanation:

Given that,

length of string = 1.5 m

Mass of the string = 5 g

Tension = 50 N

Suppose, The vibrations produce the sound with the same frequency. What is the wavelength of the sound emitted by the string

(a). We need to calculate the wavelength of waves of the string

Using formula of length

Here, n = 3

Put the value into the formula

(b). We need to calculate the frequency

Using formula of frequency

Put the value into the formula

(c). We need to calculate the wavelength of the sound emitted by the string

Using formula of wavelength

Put the value i to the formula

Hence, (a). The wavelength of waves of the string is 1 m.

(b). The frequency of the waves is 122.4 Hz.

(c). The wavelength of the sound emitted by the string is 2.8 m.

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg