A900-kg car initially at rest rolls 50 m down a hill inclined at an angle of 5.0°. a 400-n effective friction force opposes its motion.
a. what distance will it travel on a similar horizontal surface (assume the friction force is the same) at the bottom of the hill?
b. if the friction force remains the same will the distance decrease or increase if the car's mass is 1800 kg?
o will decrease
o will increase
o will remain the same

d = 146.2 m

increase

Explanation:

Using Energy Balance:

U_i + W =  U_f

K_i + U_gi + W = K_f + U_fg

0 + m*g*h + F*d = 0.5*m*v_f^2

(900)*(9.81)*(50 sin (5)) + 400*50 = 0.5*900*v_f^2

v_f^2 = 129.944

v_f = 11.4 m/s at the bottom of the hill

U_i + W =  U_f

K_i + U_gi + W = K_f + U_fg

0.5*m*v_i^2 - F*d = 0

0.5*900*129.944 = 400*d

d = 146.19 m

part b

Heavier car will gain greater momentum at the bottom of the hill and attain a higher velocity at the bottom; hence, the distance will increase.

increase

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.

the components of a vector are the parts of the vectors that are to each other.

b perpendicular