Agolf ball is hit from the ground into the air with an initial velocity of 64 ft/sec. how many seconds will it take for the golf ball to return to the ground of h=64t-16t^2 represents the height of the ball above the ground t sec after it is hit

Explanation:

Given a quadratic equation in its standard form:

It's roots can be found using the quadratic formula, given by:

That's what we need to do in this problem, because we need to know for what values of t h(t)=0:

In this case:

So:

We are not interested in the first solution t=0 because it is the time before  the golf ball is hit from the ground. The answer we look is the second solution t=4.

Therefore,  it takes 4 seconds to return to the ground.

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.