If one star has a temperature of 5200 k and another star has a temperature of 7900 k, how much more energy per second will the hotter star radiate from each square meter of its surface?

5.327

Explanation:

Stefan-Boltzmann law states that the total radiant heat power emitted from a surface is proportional to the fourth power of its absolute temperature.

                                     W = σT⁴

Where,

W is the total radiant heat power emitted from a surface

σ is  constant of proportionality, called the Stefan–Boltzmann constant = 5.67 × 10⁻⁸ Wm⁻²K⁻⁴

T is absolute temperature in kelvin

For the first star, T = 5200 K

                          ∴  W₁ = σ(5200)⁴

For the second star, T = 7900 K

                          ∴  W₂ = σ(7900)⁴

The amount of energy radiated by the hotter star W₂, with respect to the other star W₁  is,

                       W₂ / W₁  = σ(7900)⁴ / σ(5200)⁴

pretty sure it's false

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .