The bullet starts at rest in the gun. an 8.6 g bullet leaves the muzzle of a rifle with a speed of 430.1 m/s. what constant force is exerted on the bullet while it is traveling down the 0.5 m length of the barrel of the rifle?

The constant force exerted on the bullet is 1590.87 N.

Explanation:

It is given that,

Mass of the bullet, m = 8.6 g

Initial speed of the bullet, u = 0          

Final speed of the bullet, v = 430.1 m/s

We need to find the force exerted on the bullet while it is traveling down the 0.5 m length of the barrel of the rifle. Let a is the acceleration of the bullet. So,

Let F is the force exerted. It is given by :

F = 1590.87 N

So, the constant force exerted on the bullet is 1590.87 N. Hence, this is the required solution.                                                  

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.