An alpha particle (atomic mass 4.0 units) experiences an elastic head-on collision with a gold nucleus (atomic mass 197 units) that is originally at rest. what is the fractional loss of kinetic energy for the alpha particle

0.08

Explanation:

The alpha particle suffers a head-on collision with the gold nucleus, so it retraces it path after the collision.

Let us take the masses of the particles in atomic mass units.

The initial momentum and kinetic energy of the gold nucleus is 0(since it is stationary). So, applying conservation of momentum and energy, we get the following two equations:

     ..........(1)

      ..........(2)

where,

= mass of the alpha particle = 4 units

= mass of the gold nucleus = 197 units

= initial velocity of the alpha particle

= final velocity of the alpha particle

= final velocity of the gold nucleus

Now, we shall substitute the value of from equation (1) in equation (2). After some simplifications, we get,

Dividing both sides by and substituting and , we get,

or,

Here,

Therefore,

or,

Our required solution is -0.96 because the final velocity() of the alpha particle will be a little less the initial velocity(). The negative sign comes as the alpha particle reverses it's direction after colliding with the gold nucleus.

Fractional change in kinetic energy is given by,

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation:

and 1and 1