Temperature change time base problem. suppose v = 24 v, i = 0.1 a, for water: mw = 51 gm, cw = 4.18 j/gm ∘k-1, for resistor: mr = 8 gm, and cr = 3.7 j/gm ∘k-1. if the water is initially at room temperature, how long will it take for the water to heat up 5∘k? (hint: dt/dt is approximately equal to δ t / δt .)

t = 444.125 sec

Explanation:

Given data:

V = 24 volt

I  = 0.1 ampere

mass of water mw = 51 gm

cr = 4.18 J/gm degree K^-1

mass of resistor = 8 gm

cr = 3.7 J/gm degree K^-1

we know that power is given as

Power P = VI

But P =E/t

so equating both side we have

solving for t

t = 444.125 sec

Explanation:

Given:

Now the amount of heat required to heat the water by 50 K:

Now the amount of heat required to heat the resistor by 50 K:

Now the total heat to converted from the electrical energy:

Now Using Joule's law of heating:

an obstruction