What is the change in temperature of a 2.50 l system when its volume is reduced to 1.00 l if the initial temperature was 298 k?

-178.8 K

Explanation:

From Charles law,

V₁/T₁ = V₂/T₂ Equation 1

Where V₁ = Initial volume, T₁ = Initial Temperature, V₂ = Final volume, T₂ = Final Temperature.

Making T₂ the subject of the equation

T₂ = V₂T₁/V₁ Equation 2

Given: V₂ = 1.00 L, V₁ = 2.5 L, T₁ = 298 K.

Substitute into equation 2

T₂ = 1.00(298)/2.5

T₂ = 119.2 K.

But,

Change in temperature = T₂ - T₁ = 119.2-298

Change in temperature = -178.8 K.

Hence the change in temperature = -178.8 K

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