A 2.5-kg object is dropped from a height of 1000 m. what is the force of air resistance on the object when it reaches terminal velocity

24.5 N

Explanation:

The falling object experiences its weight acting downwards and the air resistance in the opposite direction.

The air resistance increases with velocity so there may come a point, depending on the shape of the object and if there is sufficient height, where these 2 forces are equal.

Since the object has no net forces acting on it it will, according to Newton, no longer accelerate but continue with a constant velocity.

This is called Terminal Velocity.

So:

Air resistance = weight

R = m g

R = 2.5 × 9.8  = 24.5N

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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according to jean piaget, in what stage of cognitive development are children able to understand conservation task?

b. preoperational

just took it