An electron passing through Point Ain the electric fieldhad thespeed of 107 m/s and atPoint Bthe speed of2×107m/s.
(a) Determine the electric potential difference between points Aand B.
(b) What would be the electron speed atPoint B, if atPoint Athe speed were zero?

a) Electric potential = 853 V

b) Electron speed at point B, if at Point A, the speed were zero = 1.732 × 10⁷ m/s

Explanation:

For an electron moving in an electric field with potential V,

Work done = qV where q is the charge on the electron

And the Work done is equal to the change in kinetic energy of the electron

qV = m(v₂² - v₁²)/2

V = m(v₂² - v₁²)/2q

q = 1.602 × 10⁻¹⁹C

m = 9.11 × 10⁻³¹ kg

v₁= 10⁷ m/s

v₂ = 2 × 10⁷ m/s

Putting these values in for the variables and solving

V = 853 V

b) If the electron started from rest,

qV = mv²/2

v = √(2qV/m) =√((2 × (1.602 × 10⁻¹⁹) × 853)/(9.11 × 10⁻³¹)) = 1.732 × 10⁷ m/s

explanation:

earth's surface is mainly heated by the absorption of infrared radiation from the sun.

evaporation occurs because molecules in liquid water are warmed ( usually by the sun) and vibrate quicker, becoming less dense and rise.

condensation occurs because molecules in water vapor are cooled and therefore vibrate more slowly thus becoming more dense and eventually fall to earth.

lines of equal barometric pressure on a weather map are called: isobars : lines of equal temp on a weather map are called: isotherms.​

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered