A defibrillator passes 14.0 A of current through the torso of a person for 0.0300 s. How much charge moves in coulombs?

4.2 C

The charge (Q) moving is the product of the current(I) flowing through the torso of the person and the time taken (t) for the flow.

i.e

Q = I x t

Where;

I = current = 14.0A

t = time taken  = 0.0300s

Substituting the values of I and t into the equation above gives

Q = 14.0 x 0.0300

Q = 4.2 C

Therefore quantity of charge moving is 4.2 C

hèllo, sorry i really need some more points so if you need this qustion answered than retype it

see earlier