What is the rate at which work is done in lifting a 35-kilogram object vertically at a constant speed of 5.0 meters per second?

1.75 kW

Explanation:

First, the rate at which work is done is simply termed Power

m = 35kg

v = 5.0 m/s

since the undergoes a vertical motion g = 10 m/s²

F = W = mg = 35×10 = 350 N

Power = Fv = 350×5 = 1750 Watt

the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

the dependent variable, the one that you measure the response in, is the distance that the washers travel.

conduction, convection, radiation