A potential difference Δ V exists between the inner and outer surfaces of the membrane of a cell. The inner surface is negative relative to the outer surface. If 1.00 × 10 − 20 J of work is required to eject a positive potassium ion (K + ) from the interior of the cell, what is the magnitude of the potential difference (in millivolts) between the inner and outer surfaces of the cell?

The magnitude of the potential difference between the inner and outer surfaces of the cell is 0.0625 V

Explanation:

Given that,

Work done

We need to calculate the magnitude of the potential difference between the inner and outer surfaces of the cell

Using formula of wok done

Where,

V = volt

W = work done

q = charge

Put the value into the formula

Hence, The magnitude of the potential difference between the inner and outer surfaces of the cell is 0.0625 V

hey , the answer is c

the total distance traveled by the car is

30km + 49km = 79 km .