The potential at location A is 382 V. A positively charged particle is released there from rest and arrives at location B with a speed vB. The potential at location C is 785 V, and when released from rest from this spot, the particle arrives at B with twice the speed it previously had, or 2vB. Find the potential at B.

247.67 V

Explanation:

Given

Potential At A

Potential at

when particle starts from A it reaches with velocity at Point while when it starts from C it reaches at point B with velocity

Suppose m is the mass of Particle

Change in Kinetic Energy of particle moving under the Potential From A to B

Change in Kinetic Energy of particle moving under the Potential From C to B

Divide 1 and 2 we get

on solving we get

the inner core.

good luck: )

klicker

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