An ice cube measures 1.38 in. on each edge and weighs 1.39 oz. What is the density of the ice cube in g/cm^3

0.91 g/cm³

Explanation:

Density: This can be defined as the ratio of mass of an object to its volume.

The mathematical expression for density is given as,

D = m/v Equation 1

Where D = Density of the ice cube, m = mass of the ice cube, v = volume of the ice cube.

v = l³

Where l = length of each side of the cube.

l = 1.38 in = (1.38×2.54) cm = 3.51 cm

v = 3.51³

v = 43.24 cm³

Given: m = 1.39 oz = (1.39×28.35) g = 39.41 g

Substitute into equation 1

D = 39.41/43.24

D = 0.91 g/cm³

Hence the density of the ice cube = 0.91 g/cm³

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

not too sure thinking all accelerations are pointed down