A sprinkler mounted on the ground sends out a jet of water at a 20 ∘ angle to the horizontal. The water leaves the nozzle at a speed of 15 m/s .How far does the water travel before it hits the ground? d=?

14.47 m

Explanation:

The horizontal and vertical components of water velocity

Ignore air resistance, gravity acceleration g = -9.8 m/s2 is the only thing that affects vertical motion of water, we can use the following equation to calculate the time it takes for water to shoot up then come down and hit the ground at h = 0 m

This is also the time for water to travel horizontally at the rate of 14.1 m/s. We can use this to calculate the horizontal distance

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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