A vertical right-circular cylindrical tank measures 7 ft high and 8 ft in diameter. It is full of kerosene weighing 51.2 pounds per cubic feet. How much work does it take to pump the kerosene to the level of the top of the tank?

W = 126106 ft-lbs

Explanation:

given,

Height of the cylinder = 7 ft

Diameter of cylinder = 8 ft

radius of the cylinder = 4 ft

Weight of the kerosene = 51.2 lb/ft³

Calculating the volume of cylinder for dy height

dV = π r² dy

dV = π 4² dy

dV = 16πdy

Force acting on the cylinder

dF = W x dV

dF = 51.2 x 16πdy..........(1)

We know

work done = Force x displacement

displacement = 7 - y

dW = 51.2 x 16πdy x (7 - y)

integrating both side

on solving

W = 126106 ft-lbs

Hence, Work done to pump the kerosene is equal to W = 126106 ft-lbs

no simpler subs form complex ones. synthesise = make

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.