Two objects form a closed system. One object, which is at 400 K, absorbs 25.0 kJ of heat from the other object, which is at 500 K. What is the net change in entropy ΔSsysΔSsysDeltaS_sys of the system? Assume that the temperatures of the objects do not change appreciably in the process

Explanation:

The given data is as follows.

        = 400 K,     = 500 K,  

= 25 kJ = 25000 J   (as 1 kJ = 1000 J)

Now, we will calculate the change in entropy as follows.

Putting the given values into the above formula as follows.

                      =      

                      = 250 J/K

Hence, we can conclude that change in entropy is 250 J/K.

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.

pecialized keyboards