Railroad car A, with mass 6275 kg, is traveling east at 6.5 m/s along a straight track. It strikes railroad car B, with mass 5155 kg, which is also traveling east along the same track at 3.8 m/s. The two railroad cars stick together. Assume the track is frictionless.

How Fast do the two attached railroad cars move immediately after the collision?

The conservation of momentum is used measure the final velocity. The velocity of  the two attached railroad cars after collisision is 5.28 m/s.

The velocity of  the two attached railroad cars  can be calculated by the conservation of momentum formula,

Where,

- mass of Railroad car A = 6275 kg

- velocity of the Railroad car A = 6.5 m/s

- mass of the railroad car B = 5155 kg

- velocity of the railroad car B =  3.8 m/s

Put the values in the formula and calculate for

Therefore, the velocity of  the two attached railroad cars after collisision is 5.28 m/s.

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The speed of A and B immediately after collision is 5.28m/s

Explanation:

Mass of A is 6275kg

Speed of A is 6.5m/s

Mass of B is 5155kg

Speed of B is 3.8m/s

Track is frictionless.

A and B stick together.

speed of attached A and B = ?

mₐsₐ + mᵇsᵇ = (mₐ + mb) s

Therefore, The speed of A and B immediately after collision is 5.28m/s

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )

answerdmitry mendeleyev made a workable classification of the elements