Two point charges, +2.80 μC and -6.20 μC, are separated by 2.30 m. What is the electric potential midway between them?

V=-26651.7V

Explanation:

The electric potential is for an electric charge is expressed as

V=kq/r.

Where K is constant, q is the charge and r is the distance.

Hence for a charge of +2.80 μC and - 6.20μC, both at distance 2.3m to each other, we can calculate the electric potential midway between them as

V=(kq/r)-(kq/r)

Since the mid way distance is 2.3/2=1.15m

Hence

V=K[(q/1.15) - (q/1.15)]

V=9*10⁹*10⁻⁶(2.43-5.39)

V=-26651.7V

a, c, d, e are all applying about success strategies.

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )