A particle with a charge of +4.0 μC has a mass of 5.0 g. What magnitude electric field directed upward will exactly balance the weight of the particle?

E = 12262 V/m

Explanation:

given,

Charge of the particle, q = +4.0 μC

mass of the ball, m = 5 g

Electric field, E = ?

Force due to weight

F = m g

Force due to electric field

F =q E

To balance the weight of particle both the forces must be equal

Electric field exerted on the ball will be equal to

m g = q E

E = 12262 V/m

Hence, the electric field acting in the particle is equal to E = 12262 V/m

second mirror gathers light from a faraway object and reflects it to another mirror. - a.

are there options? cause you ain’t. real specific