Physics, 13.02.2020 18:18 domo1812

Calculate the electric field (magnitude and direction) at the upper right corner of a square 1.22 m on a side if the other three corners are occupied by 2.40×10−6 C charges. Assume that the positive x-axis is directed to the right.

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Answer from: Dreambig85

Explanation:

It is mentioned that the magnitude of given charge is $2.40 \times 10^{-6} C$ and side of the square is 1.22 m.

Hence, we will calculate the electric field due to charge at point A as follows.

$E_{a} = k\frac{q}{r^{2}}$

= $\frac{9 \times 10^{9} \times 2.4 \times 10^{-6}}{(1.22)^{2}}$

= $14.512 \times 10^{3} N/C$ (acts along y-axis)

Electric field at D due to the charge at C is as follows.

$E_{c} = k\frac{q}{r^{2}}$

= $\frac{9 \times 10^{9} \times 2.4 \times 10^{-6}}{(1.22)^{2}}$

= $14.512 \times 10^{3} N/C$ (acts along y-axis)

Electric field at D due to the charge at B is as follows.

$E_{d} = k\frac{q}{r^{2}}$

= $\frac{9 \times 10^{9} \times 2.4 \times 10^{-6}}{(1.7253)^{2}}$

= $7.2564 \times 10^{3} N/C$

Now, we will resolve it into two components.

$E_{bx} = E_{b} Cos 45 = 5.1318 \times 10^{3} N/C$

$E_{by} = E_{b} Sin 45 = 5.1318 \times 10^{3} N/C$

Now, the resultant x component is as follows.

$E_{x} = (14.512 + 5.1318) \times 10^{3} = 19.6438 \times 10^{3} N/C$

Resultant y component is given as follows.

$E_{y} = (14.512 + 5.1318) \times 10^{3} = 19.6438 \times 10^{3} N/C$

Therefore, resultant electric field at point D is as follows.

$E = \sqrt{E^{2}_{x} + E^{2}_{y}}$

= $\sqrt{(19.6438 \times 10^{3})^{2} + (19.6438 \times 10^{3})^{2}}$

= $27.780 \times 10^{3} N/C$

And, the direction of electric field is

$\theta = tan^{-1} (\frac{E_{y}}{E_{x}})$

= $tan^{-1} (1)$

= $45^{o}$

This means that net electric field makes an angle of $135^{o}$ with positive x-axis in counter clockwise direction.

Answer from: Quest

Answer: it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.explanation: we have equation of motion $s=ut+\frac{1}{2} at^2$ ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/s $s=0*t+\frac{1}{2} *2.18*t^2$ $s=1.09t^2[/ 2equating equation 1 and 2 [tex]4.75t = 1.09t^2\\ \\ t=4.36 seconds.$ so it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.

Answer from: Quest

Molybdeum(mo)orruthenium (ru)actually, elements with similar chemical properties as technetium would bemn, re, and bh. this is because elements in the same group/family (column) have similar chemical properties. elements in the same period (row) have the same number of energy levels (or shells).

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Calculate the electric field (magnitude and direction) at the upper right corner of a square 1.22 m...

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