Precisely 1.50 s after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 2.20 m/s2 , how much time passes before the police car overtakes the speeder after the speeder passes (assumed moving at constant speed)

11.42 s

Explanation:

Assuming the speed of the police car = 99 Km/h

       v = 99 km/h x 0.278 = 27.52 m/s

Speed of the Passer = 133 Km/h

       u = 133 x 0.278 = 37 m/s

acceleration of the police car = 2.20 m/s²

time taken to overtake passer = ?

distance travel by the passer in t second.

x = u t

x = 37 t

Distance traveled by the police

both the distance are same so,

37 t = 27.52 t +1.1 (t-1.5)²

8.62 t = t² + 2.25 - 3t

t² -11.62 t + 2.25 = 0

on solving the above equation we get

t = 11.42 s , 0.92 s

neglecting the second value because it is less than 1.5 s.

Time taken by the driver to overtake the passer is equal to 11.42 s

a electromagnetic waves

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force