We wish to determine the electric field at a point near a positively charged metal sphere (a good conductor). We do so by bringing a small positive test charge q0, to this point and measure the force F0 on it. F0/q0 will be the electric field E as it was that point before the test charge was present. a. greater thanb. less thanc. equal to

Less than.

Explanation:

We have the positive charged metal sphere and we have to determine the electric field at a point near to it. In order to find that if we bring the positive test charge at that point then as we know that "like charges repel" so their electric field lines will repel each other resulting in a weaker electric field.    

    However if we bring the negative test charge at that point then of course there will be attraction and also the the electric field lines will direct from the positive to negative resulting in a stronger electric field between them. So there will be larger electric field then before.

"In this case, It can be concluded that electric field will be less than it was at this point before the test charge was present."

answer: question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation:

where are the vectors ?