The charges are in a uniform electric field whose direction makes an angle of 36.3 ∘∘ with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 7.60×10−9 N⋅mN⋅m ?

E=828N/C

Explanation:

Suppose the point charges are q1=-500nC

q2=+500nC

Distance(l)=3.10mm

Now to calculate dipole moment:

Dipole moment (p)=q*l

=(5.0*10'-9C)(3.10*10'-3m)

p=15.50*10'-12C.m

Now to calculate magnitude:

E=torque(£)/[email protected]=7.6*10'-9/(15.50*10'-12C.m)(sin36.3)

E=7.6*10'-9/9.17*10'-12

E=828N/C

Or

E=8.28*10'2N/C

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

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