What is the deceleration (in m/s2) of a rocket sled if it comes to rest in 1.7 s from a speed of 1020 km/h? (Such deceleration caused one test subject to black out and have temporary blindness.)

40.47m/s²

Explanation:

Acceleration is the change in velocity of a body with respect to time.

Acceleration = change in velocity/time

Given speed = 1020km/hr

Time = 1.7s

Converting 1020km/hr to m/s we have;

(1020×1000/3600)m/s

= 1,020,000/3,600

= 283.3m/s

Acceleration = 283.3/7

Acceleration = 40.47m/s²

Deceleration is therefore 40.47m/s²

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2