If the force of friction on the crate is a steady 70 N, find the KE gained by the crate

The kinetic energy gained by the crate is 300 Joules

Calculate the KE gained by the crate.

KE gained = 30 * 10

KE gained = 300 Joules

Hence the kinetic energy gained by the crate is 300 Joules

Learn more about kinetic energy here: link

Complete question:

How much work is done when you push a create horizontally with 100 N across a 10 m factory floor?

b) if the force of friction on the crate is a steady 70 N, show that the KE gained by the crate is

How much work is done when you push a create horizontally with 100 N across a 10 m factory floor?

b) if the force of friction on the crate is a steady 70 N, show that the KE gained by the crate is

300 J

Explanation:

The net work gives the kinetic energy gained. The net force will be 100 N-70 N= 30 N

Work is a product of force and distance hence

Net work=30*10=300 J

Therefore, the kinetic energy gained is 300 N. I assume the first part of the question was already answered

so easy. just google the electromagnetic waves and it’ll pop up.

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.