If the L-shaped rod has a moment of inertia I=9kgm2, F1=12N, F2=27N, and again F3=0, how long a time t would it take for the object to move through 45∘ ( π/4 radians)? Assume that as the object starts to move, each force moves with the object so as to retain its initial angle relative to the object. Express the time in seconds to two significant figures.

Time, t = 2.80seconds

Explanation:

Calculating net Torque, T

Torque(net)= F2(0.08m) - F1(0.03)

Torque(net) = (27×0.08)-(12×0.03)

Torque(net)= 2.16 - 0.36 =1.8N/m

Pi/4= Torque(net)/ Inertia

3.142/4= 1.8/9 = 0.2rad/s^2=a

Pi/4= 1/2 at^2

3.142/4=1/2×0.2 ×t^2

0.7855= 0.1 t^2

t = sqrt(0.7856/0.1)

t= sqrt(7.855)

t=2.80 seconds

"i have always loved contemporary art and made it a general goal to work within the field. after a few nonprofit internships at museums and galleries, i decided to try the for-profit art world and was offered a job as the ad assistant at the magazine. i much prefer the pace of the for-profit art community and have stayed with the company for three years, with a promotion to an account manager last spring."

i just did this and got a 100.

yup its correct its: c) b b