A 4.65 g bullet moving at 824 m/s penetrates a tree to a depth of 5.23 cm . Use energy considerations to find the average frictional force that stops the bullet. Answer in units of N.

30183.92 N

Explanation:

Force: This can be defined as the product of the mass of a body and it's acceleration. The S.I unit of force is Newton (N).

From the question,

The kinetic energy of the bullet = Work done by friction in the tree in stopping the bullet.

1/2mv² = Fₓd Equation 1

Where m = mass of the bullet, v = velocity of the bullet, Fₓ = average Frictional force exerted by the tree on the bullet, d = depth of penetration.

Make Fₓ the subject of the equation,

Fx = mv²/2d Equation 2

Given: m = 4.65 g = 0.00465 kg, v = 824 m/s, d = 5.23 cm = 0.0523 m.

Substitute into equation 2

Fₓ = 0.00465(824)²/(2×0.0523)

Fₓ = 30183.92 N.

Hence the average frictional force = 30183.92 N

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.