Physics, 18.02.2020 17:42 brookeguilford
Water flows at speed of 5.9 m/s through a horizontal pipe of diameter 3.1 cm . The gauge pressure P1 of the water in the pipe is 1.5 atm . A short segment of the pipe is constricted to a smaller diameter of 2.1 cm. What is the gauge pressure of the water flowing through the constricted segment?
Answers: 1
![v_{1} = 5.9[m/s]\\d_{1} = 3.1[cm] = 0.031[m]\\ P_{1}=1.5[atm]= 1.5[atm]*\frac{101.325kPa}{1atm} = 151.98[kPa]](/tpl/images/0514/2372/12b57.png)
![d_{2}=2.1[cm]=0.021[m]](/tpl/images/0514/2372/6b1ad.png)
![dens_{1}= dens_{2}=dens=1000[kg/m^{3}]](/tpl/images/0514/2372/4918c.png)
![Q=v_{1}*(\frac{\pi }{4}*0.031^{2} ) \\Q = 5.9*(\frac{\pi }{4}*0.031^{2} )\\Q=4.45*10^{-3}[m^{3}/s]](/tpl/images/0514/2372/348a5.png)
![v_{2} =\frac{Q*4}{\pi *0.021^{2} } \\v_{2}=\frac{0.004453*4}{\pi *0.021^{2} }\\v_{2}=12.85[m/s]](/tpl/images/0514/2372/5fafa.png)
![P_{2} =P_{1}+\frac{1}{2} *dens*v_{1}^{2} -\frac{1}{2} *dens*v_{2}^{2}\\P_{2} =101325+\frac{1}{2} *1000*5.9^{2} -\frac{1}{2} *1000*12.85^{2}\\P_{2}=36168.75[Pa]](/tpl/images/0514/2372/fa2dc.png)
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Water flows at speed of 5.9 m/s through a horizontal pipe of diameter 3.1 cm . The gauge pressure P1...
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